Two Pass Assembler

#include< stdio.h>
#include< conio.h>
#include< string.h>
#define lines_in_program 9
void print(char *p,int loc,int len,char ra)
{printf("%s\t%d\t%d\t%c\n",p,loc,len,ra);}
void main()
{
char *p[9][4] = {{"PRG1","START","",""},{"","USING","*","15"},
{"","L","1","FIVE"}, {"","A","1","FOUR"},
{"","ST","1","TEMP"}, {"FOUR","DC","F'4'",""},
{"FIVE","DC","F'5'",""}, {"TEMP","DS","1F",""},
{"","END","",""}};
int i,j=0,location_counter=0;
clrscr();
for (i=0;i< 9;i++)
{ for(j=0;j< 4;j++)
printf("%s\t",p[i][j]);
printf("\n");
}
printf("\n\n\n\n Symbol ");
printf("Table:\nSYMBOL\tVALUE\tLENGTH\tRelocatable/Absolute\n");
printf("---------------------------------------------\n");
for(i=0;i< 9;i++)
{ if(strcmp(p[i][1],"START")==0)
print(p[i][0],location_counter,1,'R');
else if(strcmp(p[i][0],"")!=0)
{
print(p[i][0],location_counter,4,'R');
location_counter=4+location_counter;
}
else if(strcmp(p[i][1],"USING")==0){}
else{location_counter=4+location_counter;}
}
getch();
}


/*OUTPUT:
PRG1 START
USING * 15
L 1 FIVE
A 1 FOUR
ST 1 TEMP
FOUR DC F'4'
FIVE DC F'5'
TEMP DS 1F
END

Symbol Table:
SYMBOL VALUE LENGTH Relocatable/Absolute
---------------------------------------------
PRG1 0 1 R
FOUR 12 4 R
FIVE 16 4 R
TEMP 20 4 R */

Two Pass Assembler

#include< stdio.h>
#include< string.h>
#include< conio.h>


void main()
{
char *code[9][4]={
{"PRG1","START","",""},
{"","USING","*","15"},
{"","L","",""},
{"","A","",""},
{"","ST","",""},
{"FOUR","DC","F",""},
{"FIVE","DC","F",""},
{"TEMP","DS","1F",""},
{"","END","",""}
};
char av[2],avail[15]={'N','N','N','N','N','N','N','N','N','N','N','N','N','N','N'};
int i,j,k,count[3],lc[9]={0,0,0,0,0,0,0,0,0},loc=0;
clrscr();
printf("----------------------------------------------------\n");
printf("LABEL\t\tOPCODE\n");
printf("----------------------------------------------------\n\n");
for(i=0;i< =8;i++)
{
for(j=0;j< =3;j++)
{
printf("%s\t\t",code[i][j]);
}
j=0;
printf("\n");
}
getch();
printf("-----------------------------------------------------");
printf("\nVALUES FOR LC : \n\n");
for(j=0;j< =8;j++)
{
if((strcmp(code[j][1],"START")!=0)&&(strcmp(code[j][1],"USING")!=0)&&(strcmp(code[j][1],"L")!=0))
lc[j]=lc[j-1]+4;
printf("%d\t",lc[j]);
}
printf("\n\nSYMBOL TABLE:\n----------------------------------------------------\n");
printf("SYMBOL\t\tVALUE\t\tLENGTH\t\tR/A");
printf("\n----------------------------------------------------\n");

for(i=0;i< 9;i++)
{
if(strcmp(code[i][1],"START")==0)
{
printf("%s\t\t%d\t\t%d\t\t%c\n",code[i][0],loc,4,'R');
}
else if(strcmp(code[i][0],"")!=0)
{
printf("%s\t\t%d\t\t%d\t\t%c\n",code[i][0],loc,4,'R');
loc=4+loc;
}
else if(strcmp(code[i][1],"USING")==0){}
else
{loc=4+loc;}
}
printf("----------------------------------------------------");

printf("\n\nBASE TABLE:\n-------------------------------------------------------\n");
printf("REG NO\t\tAVAILIBILITY\tCONTENTS OF BASE TABLE");
printf("\n-------------------------------------------------------\n");
for(j=0;j< =8;j++)
{
if(strcmp(code[j][1],"USING")!=0)
{}
else
{
strcpy(av,code[j][3]);
}
}
count[0]=(int)av[0]-48;
count[1]=(int)av[1]-48;
count[2]=count[0]*10+count[1];
avail[count[2]-1]='Y';

for(k=0;k< 16;k++)
{
printf(" %d\t\t %c\n",k,avail[k-1]);
}

printf("-------------------------------------------------------\n");
printf("Continue..??");
getchar();
printf("PASS2 TABLE:\n\n");
printf("LABEL\t\tOP1\t\tLC\t\t");
printf("\n----------------------------------------------------\n");
loc=0;
for(i=0;i< =8;i++)
{
for(j=0;j< =3;j++)
{
printf("%s\t\t",code[i][j]);
}
j=0;
printf("\n");
}
printf("-----------------------------------------------------");

getch();

}
/*
----------------------------------------------------
LABEL OPCODE
----------------------------------------------------

PRG1 START
USING * 15
L
A
ST
FOUR DC F
FIVE DC F
TEMP DS 1F
END



-----------------------------------------------------
VALUES FOR LC :

0 0 0 4 8 12 16 20 24

SYMBOL TABLE:
----------------------------------------------------
SYMBOL VALUE LENGTH R/A
----------------------------------------------------

PRG1 0 4 R
FOUR 12 4 R
FIVE 16 4 R
TEMP 20 4 R


----------------------------------------------------

BASE TABLE:
-------------------------------------------------------
REG NO AVAILIBILITY CONTENTS OF BASE TABLE
-------------------------------------------------------
0 -----------------------------------
1 N
2 N
3 N
4 N
5 N
6 N
7 N
8 N
9 N
10 N
11 N
12 N
13 N
14 N
15 Y

-------------------------------------------------------
Continue..??
PASS2 TABLE:

LABEL OP1 LC
----------------------------------------------------
PRG1 START
USING * 15
L
A
ST
FOUR DC F
FIVE DC F
TEMP DS 1F
END
-----------------------------------------------------


*/

Lexical Analizer

/* TO IMPLEMENT LEXICAL ANALIZER IN C */

#include< conio.h>
#include< string.h>

void main()
{
int i,j,lc;
char *a[9][4]={"PRG","START" ," " ," ",
" " ,"USING" ,"*" ,"15",
" ","L","1","FIVE",
" ","A","1","FOUR",
" ","ST","1","TEMP",
"FOUR ","DC","F","4",
"FIVE","DC","F","5",
"TEMP","DS","1","F",
" " ,"END"," "," ", };
clrscr();
printf("\n \t\t LEXICAL ANALIZER \n");

for(i=0;i< 9;i++)
{ for(j=0;j< 4;j++)
{ if(isalpha(*a[i][j]))
printf("\n STRING : %s",a[i][j]);
if(isdigit(*a[i][j]))
printf("\n DIGIT : %s",a[i][j]);
}
printf("\n");
}

getch();
}
/* OUTPUT:-

LEXICAL ANALIZER

STRING : PRG
STRING : START

STRING : USING
DIGIT : 15

STRING : L
DIGIT : 1
STRING : FIVE

STRING : A
DIGIT : 1
STRING : FOUR

STRING : ST
DIGIT : 1
STRING : TEMP

STRING : FOUR
STRING : DC
STRING : F
DIGIT : 4

STRING : FIVE
STRING : DC
STRING : F
DIGIT : 5

STRING : TEMP
STRING : DS
DIGIT : 1
STRING : F

STRING : END

*/

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Diamond In C

/* C program to display a diamond using arrays */

#include< iostream.h>
#include< conio.h>
void main()
{
int i,j;
clrscr();
int no;
cout< < "Enter A Value";
cin>>no;
for(i=no;i>=1;i--)
{
cout< < endl;
for(int k=1;k< =i;k++)
cout< < " ";

for(j=i;j< =no;j++)
cout< < "*";

for(j=i;j< no;j++)
cout< < "*";
}
//SECOND PART

for(i=no;i>=1;i--)
{
cout< < endl;
cout< < " ";
for(int k=no;k>=i;k--)
cout<<" ";

for(j=i-1;j>=1;j--)
cout< < "*";

for(j=i-1;j>1;j--)
cout<<"*";

}
getch();
}

Call By Reference in C

/* Program for inerchanging two numbers demonstrating Call By Reference in C */

#include<>
#include<>

void swap(int *,int *);

void main()
{
int x,y;
x=15;y=20;
clrscr();
printf("x=%d,y=%d\n",x,y);
swap(&x,&y);
//printf("\n%x %x",&x,&y);
printf("\n after interchanging x=%d,y=%d\n",x,y);
getch();
}

void swap(int *u,int *v)
{
int temp;
temp=*u;
*u=*v;
*v=temp;

return;
}

Call by Values in C

/* Program on interchanging two numbers demonstrating Call By Values in C*/
#include< stdio.h>
#include< conio.h>
void main()
{
int x,y;
x=15;y=20;
clrscr();
printf("x=%d,y=%d\n",x,y);
swap(x,y);
printf("\n after interchanging x=%d,y=%d\n",x,y);
getch();
}
swap(int u,int v)
{
int temp;
temp=u;
u=v;
v=temp;
return;
}

Pointers example

/* Example of pointers in C. Thsi program uses a function to modify a string using pointers */

#include< stdio.h>
#include< conio.h>
void main()
{
void getstr(char *ptr_str,int *ptr_int);
int var=5;
char *pstr="lionel";
clrscr();
getstr(pstr,&var);
printf("The value of var after modification using pointer in a function is %d,var");
}
void getstr (char *ptr_str,int *ptr_int)
{
printf("%s\n",ptr_str);
*ptr_int=6;
getch();
}

Two Dimentional array in C

/* C program to input and display a 2-d array*/

#include< stdio.h>
#include< conio.h>
void main()
{
int num[3][3],i,j;
clrscr();
for(i=0;i< 3;i++)
{
for(j=0;j< 3;j++)
{
scanf("%d",&num[i][j]);
}
}
for(i=0;i< 3;i++)
{
for(j=0;j< 3;j++)
{
printf("\n%d",num[i][j]);
}
printf("\n");
}
getch();
}

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ISO - OSI Model

/* Draw ISO - OSI Model using C */

#include< stdlib.h>
#include< graphics.h>
#include< conio.h>
#include< stdio.h>

void main()
{
int driver, mode;
int i,j;
driver = DETECT;
initgraph(&driver,&mode,"");

outtextxy(250,450,"ISO OSI Model");
delay(2000);
outtextxy(90,30,"Sender");
delay(500);
setcolor(6);
for(i=50;i< =350;i+=50)
{
rectangle(200,i,50,i+30);
delay(500);
}
setcolor(10);
outtextxy(70,60,"Application");
delay(500);
outtextxy(70,110,"Presentation");
delay(500);
outtextxy(70,160,"Session");
delay(500);
outtextxy(70,210,"Transport");
delay(500);
outtextxy(70,260,"Network");
delay(500);
outtextxy(70,310,"Data Link");
delay(500);
outtextxy(70,360,"Physical");
delay(500);
setcolor(15);
outtextxy(390,30,"Receiver");
delay(500);
setcolor(6);
for(i=50;i< =350;i+=50)
{
rectangle(350,i,500,i+30);
delay(500);
}
setcolor(10);
outtextxy(370,60,"Application");
delay(500);
outtextxy(370,110,"Presentation");
delay(500);
outtextxy(370,160,"Session");
delay(500);
outtextxy(370,210,"Transport");
delay(500);
outtextxy(370,260,"Network");
delay(500);
outtextxy(370,310,"Data Link");
delay(500);
outtextxy(370,360,"Physical");
delay(500);
// sender Lines
line(120,80,120,100);
delay(500);
line(120,130,120,150);
delay(500);
line(120,180,120,200);
delay(500);
line(120,230,120,250);
delay(500);
line(120,280,120,300);
delay(500);
line(120,330,120,350);
delay(500);
line(120,380,120,400);
delay(500);
// Physical Connection
line(120,400,420,400);
// Receiver Lines
line(420,380,420,400);
delay(500);
line(420,330,420,350);
delay(500);
line(420,280,420,300);
delay(500);
line(420,230,420,250);
delay(500);
line(420,180,420,200);
delay(500);
line(420,130,420,150);
delay(500);
line(420,80,420,100);
//virtual connection
setcolor(15);
delay(500);
outtextxy(210,35,"Virtual Connection");
delay(1000);
for(j=65;j< =365;j+=50)
{
for(i=0;i< 15;i++)
{
setcolor(i);
line(200,j,230,j);
delay(10);
line(235,j,265,j);
delay(10);
line(270,j,300,j);
delay(10);
line(305,j,335,j);
delay(10);
line(340,j,350,j);
delay(10);
}
}
delay(500);
}
/*

*/

PC to PC Communication using RS-232

/*Aim: PC to PC Communication using RS-232 in 'C'. */

#include
#include
#define COM1 0
#define DATA_READY 0x100
#define SETTINGS ( 0x80 | 0x02 | 0x00 | 0x00)
int main(void)
{
int in, out, status;
bioscom(0, SETTINGS, COM1); /*initialize the port*/
cprintf("Data sent to you: ");
while (1)
{
status = bioscom(3, 0, COM1); /*wait until get a data*/
if (status & DATA_READY)
if ((out = bioscom(2, 0, COM1) & 0x7F) != 0) /*input a data*/
putch(out);
if (kbhit())
{
if ((in = getch()) == 27) /* ASCII of Esc*/
break;
bioscom(1, in, COM1); /*output a data*/
}
}
return 0;
}

/* OUTPUT:-
Data sent to you: HI...how are you??
*/

DIJKSRTRA'S ALGORITHM

/*Implementation of Shortest Path Algorithm(DIJKSRTRA's ALGORITHM) in C*/

#include< stdio.h>
#include< conio.h>
#include< process.h>
#include< string.h>
#include< math.h>
#define IN 99
#define N 6

int dijkstra(int cost[][N], int source, int target);

void main()
{
int cost[N][N],i,j,w,ch,co;
int source, target,x,y;
clrscr();
printf("\tShortest Path Algorithm(DIJKSRTRA's ALGORITHM\n\n");
for(i=1;i< N;i++)
for(j=1;j< N;j++)
cost[i][j] = IN;
for(x=1;x< N;x++)
{
for(y=x+1;y< N;y++)
{
printf("Enter the weight of the path between node %d and %d: ",x,y);
scanf("%d",&w);
cost [x][y] = cost[y][x] = w;
}
printf("\n");
}
printf("\nEnter The Source:");
scanf("%d", &source);
printf("\nEnter The target");
scanf("%d", &target);
co = dijsktra(cost,source,target);
printf("\nShortest Path: %d",co);
getch();
}

int dijsktra(int cost[][N],int source,int target)
{
int dist[N],prev[N],selected[N]={0},i,m,min,start,d,j;
char path[N];
for(i=1;i< N;i++)
{
dist[i] = IN;
prev[i] = -1;
}
start = source;
selected[start]=1;
dist[start] = 0;
while(selected[target] ==0)
{
min = IN;
m = 0;
for(i=1;i< N;i++)
{
d = dist[start] +cost[start][i];
if(d< dist[i]&&selected[i]==0)
{
dist[i] = d;
prev[i] = start;
}
if(min>dist[i] && selected[i]==0)
{
min = dist[i];
m = i;
}
}
start = m;
selected[start] = 1;
}
start = target;
j = 0;
while(start != -1)
{
path[j++] = start+65;
start = prev[start];
}
path[j]='\0';
strrev(path);
printf("%s", path);
return dist[target];
}
/***** Output *********

Shortest Path Algorithm(DIJKSRTRA's ALGORITHM

Enter the weight of the path between node 1 and 2: 2
Enter the weight of the path between node 1 and 3: 3
Enter the weight of the path between node 1 and 4: 4
Enter the weight of the path between node 1 and 5: 5

Enter the weight of the path between node 2 and 3: 5
Enter the weight of the path between node 2 and 4: 2
Enter the weight of the path between node 2 and 5: 3

Enter the weight of the path between node 3 and 4: 1
Enter the weight of the path between node 3 and 5: 4

Enter the weight of the path between node 4 and 5: 5



Enter The Source:2

Enter The target4
CE
Shortest Path: 2
*/

Calculation Of CRC

/* Calculation of CRC (Cyclic Redundancy Check)*/

#include< stdlib.h>
#include< conio.h>
#include< stdio.h>
void main()
{
int i,j,n,g,a,arr[20],gen[20],b[20],q[20],s;
clrscr();
printf("Transmitter side:");
printf("\nEnter no. of data bits:");
scanf("%d",&n);
printf("Enter data:");
for(i=0;i< n;i++)
scanf("%d",&arr[i]);

printf("Enter size of generator:");
scanf("%d",&g);
do{
printf("Enter generator:");
for(j=0;j< g;j++)
scanf("%d",&gen[j]);

}
while(gen[0]!=1);
printf("\n\tThe generator matrix:");
for(j=0;j< g;j++)
printf("%d",gen[j]);

a=n+(g-1);
printf("\n\tThe appended matrix is:");
for(i=0;i< j;++i)
arr[n+i]=0;

for(i=0;i< a;++i)

printf("%d",arr[i]);

for(i=0;i< n;++i)
q[i]= arr[i];

for(i=0;i< n;++i)
{
if(arr[i]==0)
{
for(j=i;j< g+i;++j)
arr[j] = arr[j]^0;
}
else
{
arr[i] = arr[i]^gen[0];
arr[i+1]=arr[i+1]^gen[1];
arr[i+2]=arr[i+2]^gen[2];
arr[i+3]=arr[i+3]^gen[3];
}
}
printf("\n\tThe CRC is :");
for(i=n;i < a;++i)
printf("%d",arr[i]);
s=n+a;
for(i=n;i< s;i++)
q[i]=arr[i];
printf("\n");
for(i=0;i< a;i++)
printf("%d",q[i]);
getch();
}
/* Output

Transmitter side:
Enter no. of data bits:8
Enter data:1 0 1 0 0 0 0 1
Enter size of generator:4
Enter generator:1 0 0 1

The generator matrix:1001
The appended matrix is:10100001000
The CRC is :111
10100001111
*/

LCM and HCM of two numbers

/* C++ program to calculate LCM and HCM of two numbers */
#include< stdio.h>
#include< conio.h>
void main()
{
int a,b,c;
cout< < "Enter two nos : ;
cin>>a>>b;
c=a*b;
while(a!=b)
{
if(a>b)
a=a-b;
else
b=b-a;
}
cout< < "HCM \t= " < < a;
cout< < "LCM \t= " < < c/a;
getch();
}

Simple C++ program

/* C++ program on Computer Details */

#include< iostream.h>
#include< conio.h>
#define max 80

int y;
int a = 0;
int b = 0;
long c = 0;
int d,m,p;

class computer
{
private:
char s[10],x[10],h[10];

public:
void getdata()
{
cout< < "Enter Computer Type : ";
cin>>h;
cout< < endl;
cout< < "Enter CPU Type : ";
cin>>x;
cout< < endl;
cout< < "Enter The Type Of OS : ";
cin>>s;
cout< < endl;
cout< < "Enter The Memory In MB : ";
cin>>m;
cout< < endl;
cout< < "Enter The Disk Space In GB : ";
cin>>d;
cout< < endl;
cout< < "Enter Yhe Price : ";
cin>>p;
cout< < endl;
}

int compare(int i)
{
if(m>a)
{
a = m;
b = d;
c = p;
y = i;
}
if((m==a)&&(d< b))
{
a = m;
b = d;
c = p;
y = i;
}
if((m==a)&&(d==b)&&(p< c))
{
a = m;
b = d;
c = p;
y = i;
}
return y;
}

void display()
{
cout< < "The Details Of The Best Computer Are : ";
cout< < endl;
cout< < "Disk Space :"< < d;
cout< < endl;
cout< < "Memory Space :"< < m;
cout< < endl;
cout< <"Price: "< < p;
cout< < endl;
cout< < "OS : "< < s;
cout< < endl;
cout< < "CPU : "< < x;
cout< < endl;
cout< < "Computer : "< < h;
cout< < endl;
}

};
void main()
{
clrscr();
computer d[max];
int r;
cout< < "Enter The Range : ";
cin>>r;
cout< < endl;

for(int i=0;i< r;i++)
{
d[i].getdata();
}
for(int j=0;j< r;j++)
{
d[j].compare(j);
}
d[y].display();
getch();
}

Hybrid inheritance

/******** IMPLEMENTATION OF HYBRID INHERITANCE ********/

#include< iostream.h>
#include< conio.h>

class student
{
private :
int rn;
char na[20];
public:
void getdata()
{
cout< < "Enter Name And Roll No : ";
cin>>na>>rn;
}
void putdata()
{
cout< < endl< < na< < "\t"< < rn< < "\t";
}
};

class test : public student
{
protected:
float m1,m2;
public:
void gettest()
{
cout< < endl< < "Enter your marks In CP 1 And Cp 2 :";
cin>>m1>>m2;
}
void puttest()
{
cout< < m1< < "\t"< < m2< < "\t";
}
};

class sports
{
protected:
float score;
public:
void getscore()
{
cout< < endl< < "Enter your score :";
cin>>score;
}
void putscore()
{
cout< < score< < "\t";
}
};



class results : public test , public sports
{
private :
float total;
public :
void putresult()
{
total = m1+m2+score;
cout< < total;
}
};

void main()
{
results s[5];
clrscr();
for(int i=0;i< 5;i++)
{
s[i].getdata();
s[i].gettest();
s[i].getscore();
}
cout< < "______________________________________________"< < endl;
cout< < endl< < "Name\tRollno\tCP 1\tCP 2\tScore\tTotal"< < endl;
cout< < "----------------------------------------------"< < endl;
for(i=0;i< 5;i++)
{
s[i].putdata();
s[i].puttest();
s[i].putscore();
s[i].putresult();
}
cout< < endl< < "----------------------------------------------";
getch();
}


/********** OUTPIUT **********
Enter Name And Roll No : Lionel
1

Enter your marks In CP 1 And Cp 2 :45

Enter your score :45
Enter Name And Roll No : Cyril
65

Enter your marks In CP 1 And Cp 2 :49
42

Enter your score :45
Enter Name And Roll No : Mayank
40

Enter your marks In CP 1 And Cp 2 :41
43

Enter your score :46
Enter Name And Roll No : Dylan
78

Enter your marks In CP 1 And Cp 2 :23
24

Enter your score :25
Enter Name And Roll No : Ansha
39

Enter your marks In CP 1 And Cp 2 :45
45

Enter your score :45
______________________________________________

Name Rollno CP 1 CP 2 Score Total
----------------------------------------------

Lionel 1 45 23 45 113
Cyril 65 49 42 45 136
Mayank 40 41 43 46 130
Dylan 78 23 24 25 72
Ansha 39 45 45 45 135
----------------------------------------------
*/

Multilevel Inheritance

/********* IMPLEMENTATION OF MULTILEVEL INHERITANCE *********/

#include< iostream.h>
#include< conio.h>

class student // Base Class
{
protected:
int rollno;
char *name;
public:
void getdata(int b,char *n)
{
rollno = b;
name = n;
}
void putdata(void)
{
cout< < " The Name Of Student \t: "< < name< < endl;
cout< < " The Roll No. Is \t: "< < rollno< < endl;
}
};

class test:public student // Derieved Class 1
{
protected:
float m1,m2;
public:
void gettest(float b,float c)
{
m1 = b;
m2 = c;
}
void puttest(void)
{
cout< < " Marks In CP Is \t: "< < m1< < endl;
cout< < " Marks In Drawing Is \t: "< < m2< < endl;
}
};

class result:public test // Derieved Class 2
{
protected:
float total;
public:
void displayresult(void)
{
total = m1 + m2;
putdata();
puttest();
cout< < " Total Of The Two \t: "< < total< < endl;
}
};

void main()
{
clrscr();
int x;
float y,z;
char n[20];
cout< < "Enter Your Name:";
cin>>n;
cout< < "Enter The Roll Number:";
cin>>x;
result r1;
r1.getdata(x,n);
cout< < "ENTER COMPUTER PROGRAMMING MARKS:";
cin>>y;
cout< < "ENTER DRAWING MARKS:";
cin>>z;
r1.gettest(y,z);
cout< < endl< < endl< < "************ RESULT **************"< < endl;
r1.displayresult();
cout< < "**********************************"< < endl;
getch();

}
/************ OUTPUT ************
Enter Your Name:Lionel
Enter The Roll Number:44
ENTER COMPUTER PROGRAMMING MARKS:95
ENTER DRAWING MARKS:90


************ RESULT **************
The Name Of Student : Lionel
The Roll No. Is : 44
Marks In CP Is : 95
Marks In Drawing Is : 90
Total Of The Two : 185
**********************************
*/

OPERATOR OVERLOADING - Unary

/********* IMPLEMENTATION OF OPERATOR OVERLOADING (UNARY)*********/
#include< iostream.h>
#include< conio.h>

class unary
{
private:
int x,y,z;
public:

unary(void)
{
cout< < "Enter Any Three Integer Nos. : ";
cin>>x>>y>>z;
}

void display(void)
{
cout< < endl< < " The Three Nos. Are : "< < x< < " , "< < y< < " , "< < z;
}

void operator --()
{
x = --x;
y = --y;
z = --z;
}

void operator ++()
{
x = ++x;
y = ++y;
z = ++z;
}
};

void main()
{
clrscr();
unary s;
s.display();

--s;
cout< < endl< < endl< < endl< < "******* The Decremented Values ********"< < endl;
s.display();

++s;
cout< < endl< < endl< < endl< < "******* The Incremented Values ********"< < endl;
s.display();
cout< < endl< < endl< < "***************************************";

getch();
}



/************ OUTPUT **************
Enter Any Three Integer Nos. : 4
-8
6

The Three Nos. Are : 4 , -8 , 6


******* The Decremented Values ********

The Three Nos. Are : 3 , -9 , 5


******* The Incremented Values ********

The Three Nos. Are : 4 , -8 , 6

***************************************
*/

Bubble Sort

/**** C Program For Implementation Of Bubble Sort. Sorting names entered by the user *****/
#include< stdio.h>
#include< conio.h>
#define MAX 10

char name[MAX][15];
void sort(int n)
{
int pa,cp,i,j,k,kk=0;
char temp[15];
pa=n-1;
cp=n-1;
for(i=1;i< =pa;i++)
{
for(j=1;j< =cp;j++)
{
kk=kk+1;
if(strcmp(name[j],name[j+1])>0)
{
strcpy(temp,name[j]);
strcpy(name[j],name[j+1]);
strcpy(name[j+1],temp);
}
}
printf("\n List after %d pass is ",i);
for(k=1;k< =n;k++)
printf("\n\t\t %s",name[k]);
getch();
}
clrscr();
printf("\n\t\t Total Comparisions Done : %d",kk);
}

void main()
{
int n,i,j;
clrscr();
printf("Enter How Many Names : ");
scanf("%d",&n);
if(n>MAX)
printf("\n\t\tArray Size IS Only %d",MAX);
else
{
printf("\n\t\tEnter %d Names :\n",n);
for(i=1;i< =n;i++)
{
printf("\t\t");
scanf("%s",name[i]);
}
sort(n);
printf("\n\n\t\tSorted List ");
for(i=1;i< =n;i++)
printf("\n\t\t%s",name[i]);
}
getch();
}
/********************* OUTPUT *******************
Enter How Many Names : 4

Enter 4 Names :
Malcolm
Lionel
Mayank
Pinto

List after 1 pass is
Lionel
Malcolm
Mayank
Pinto
List after 2 pass is
Lionel
Malcolm
Mayank
Pinto
List after 3 pass is
Lionel
Malcolm
Mayank
Pinto

*/